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Wednesday, January 31, 2007

How to answer this?

Once A, B & C went to a restaurant. After having tea and light refreshment they asked for bill, the amount of bill was $30. They decided to pay the bill amount on equal share. Everybody took out $10 from their pocket and paid the bill.

They were yet sitting and gossiping in restaurant, Suddenly the waiter realized that the amount of their bill was $25 not $30. He took $5 from counter and decided to return them. Then he thought they are 3 people, how will they share $5? So he has decided to keep $2 to him and return only $3 to them. He came to their table and returned them $3 with apology. Everybody took $1 and put in their pockets.

Now my question is first time everyone paid $10 later they get $1 refunded.

So everybody paid $9.

$9 X 3 = $27

The waiter put $2 in his pocket.

$27 + $2 = $29

So...... Where is the remaining $1 ???

errr...ok so where where?


link | posted by alwaysDaBabe at 4:40 PM |


1 Comments:

Blogger Noise commented at 1:06 AM~  

In case some of you are spending time to think abt the solution, here it is.

If we use the original amount which is $30 paid,
$25 to the resturant,
$3 refunded,
$2 to the waiter.

If we use the final amount which is price only $25 and each paid $9 which is total only $27,
$25 to the restaurant
$2 to the waiter.

Of course if u try to try to equate the $30 from the first time to the 2nd time, it is just against the mathematics as they are 2 different scenarios.

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